![]() placing a 50 Ohm resistor in parallel to ground would divide the output voltage by half). The front panel of this instrument shows that there is a 50 Ohm load in the output terminal, however, when I simulate my circuit, this instrument behaves like and ideal function generator and I cannot see the results of this load (e.g. I am using the Agilent Function Generator in Multisim. Primary Software: Electronics Workbench>Multisim
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